Kotlin and Android Development featuring Jetpack: Treating method as a Property (Page 111)

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1

Page 111 has:
fun playAITurn(
players: List,
currentPlayer: Player,
slots: List,
canPass: Boolean = false
): TurnResult? =
currentPlayer.selectedAI?.let { ai →
if (!canPass || ai.rollAgain(slots)) {
roll(players, currentPlayer, slots)
} else {
pass(players, currentPlayer)
}
}

Yet selectedAI() is defined in data class NewPlayer as follows:

fun selectedAI() = if (!isHuman.get()) {
    AI.basicAI.getOrNull(selectedAIPosition)
} else {
    null
}

Question: How can selectedAI() function be called using just selectedAI ??

Thank you
Mike (fairly new to Kotlin with little knowledge of Java)

2

Hey Mike!
You’re correct that selectedAI() in NewPlayer is a function, but it’s a property inside Player, which is the class referenced in the playAITurn() function.

NewPlayer calculates the AI, Player takes that value to be used later.

Hope this helps!

3

Most grateful